1^2(4x-7)=2x+6

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Solution for 1^2(4x-7)=2x+6 equation: 



1^2(4x-7)=2x+6

We move all terms to the left:

1^2(4x-7)-(2x+6)=0

We get rid of parentheses

1^2(4x-7)-2x-6=0

We add all the numbers together, and all the variables

-2x+1^2(4x-7)-6=0

We move all terms containing x to the left, all other terms to the right

-2x+1^2(4x-7)=6

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